Question

A particle covers 50 m distance when projected with an initial speed. On the same surface it will
cover a distance, when projected with double the initial speed ​

Answer 1

Answer:

In projectile motion,

Range, R=

g

u

2

sin2θ

=50m (Given)

Now, Initial speed is u

′

=2u

R

′

=

g

4u

2

sin2θ

=4×50

R

′

=200m