Physics, asked by jpsavita1420, 1 year ago

A particle covers half of the circle of radius r. Then the displacement and distance of the particle are respectively
(a) 2πr, 0
(b) 2r, πr
(c) \frac{\pi r}{2}, 2r
(d) πr, r

Answers

Answered by Ajsharma1231
21

So the correct option is (b)

Attachments:
Answered by Anonymous
5

Answer:

B) 2r

Explanation:

Distance is the total path covered by the body and is scalar. Displacement is the shortest distance between the initial and the final point with the direction from the starting to the ending point.

Distance covered of a moving body is always positive and can never be zero or negative. However, the displacement can be positive, negative or zero.

Thus, when the particle moves along half circle, it covers half the circumstance therefore distance covered is (2×π×r)/2 = π× r. Where r is radius of circle. It is diametrically opposite to the starting point of its motion, thus the displacement would be the shortest distance along the diameter =2*r

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