Question

A particle describes a horizontal circle on the smooth surface of an inverted cone. The plane of that
circle is at a height of 9.8cm above the vertex. Then the speed of the particle is
1) 0.49 ms"
2) 0.98 ms
3) 1.96 ms
4) 3.92 ms
​

Answer 1

Answer:

Acc to Newton law of motion

Ncosα=

r

mv

2

Nsinα=mg

r=htanθ=Radius of motion

r=htanθ=

r

mv

2

mg.h

r=

v

2

rg.h

v=

gh

=

9.8×.098

v=.98ms

−1

Answer 2

Answer:

Acc to Newton law of motion

Ncosα=

r

mv

2

Nsinα=mg

r=htanθ=Radius of motion

r=htanθ=

r

mv

2

mg.h

r=

v

2

rg.h

v=

gh

=

9.8×.098

v=.98ms

−1