Question

A particle es projected horizontally with speed of lomis what will be the distance of the partPele from Pts starting point after two second​

Answer 1

(i) catch (ii) were caught (iii) had caught (iv) are caught

Answer 2

Answer:

The horizontal distance covered by the projectile in time t is ut

The vertical distance covered during that time is g

2

t

2

tanθ =

horizontal distance

vertical distance

=

ut

g

2

t

2

=

2u

gt

t=

g

2u tanθ

Horizontal distance =

g

2u

2

tanθ

, vertical =

g

2u

2

tan

2

θ

So distance between point and point of projection =

(

g

2u

2

tanθ

)

2

+(

g

2u

2

tan

2

θ

)

2

=

g

2u

2

tanθ secθ