Question

A particle execute 8hm with an angular velocity and maximum acceleration of 3.5 rad/s and 7.5m/s2 respectively. The amplitude of oscillation is

Answer 1

angular velocity =3.5
acceleration = square of angular velocity × amplitude
7.5= 3.5×3.5× Amplitude
amplitude= 7.5/3.5×3.5 =0.6122449
=0.612245

Answer 2

Hey Dear,

◆ Answer -

A = 0.6122 m

◆ Explaination -

# Given -

ω = 3.5 rad/s

amax = 7.5 m/s^2

# Solution -

In SHM, angular velocity and maximum acceleration is related as -

amax = Aω^2

A = amax / ω^2

A = 7.5 / 3.5^2

A = 0.6122 m

Therefore, amplitude of SHM is 61.22 cm.

Hope this helps you. Thanks for asking..