Question

a particle executes a linear SHM of amplitude of 8cm and period 2s. what is the magnitude of its maximum velocity?

Answer 1

V = Aω where signs have their usual meaings 

V = A x 2π/T = 8/100 x 2π/2 = 0.08π m/s ANSWER

Answer 2

Formula used: V = Aω

Where,
V = velocity of particle.
A = amplitude = 8cm
ω = Angular velocity

We know that ω = 2π/t   [ given t = 2s]

V = A × 2π/t
   = 8 × 2π/2
   = 8 × 3.14
   = 25.12 cm/s or 0.2512 m/s