a particle executes a linear SHM of amplitude of 8cm and period 2s. what is the magnitude of its maximum velocity?
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V = Aω where signs have their usual meaings
V = A x 2π/T = 8/100 x 2π/2 = 0.08π m/s ANSWER
V = A x 2π/T = 8/100 x 2π/2 = 0.08π m/s ANSWER
Answered by
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Formula used: V = Aω
Where,
V = velocity of particle.
A = amplitude = 8cm
ω = Angular velocity
We know that ω = 2π/t [ given t = 2s]
V = A × 2π/t
= 8 × 2π/2
= 8 × 3.14
= 25.12 cm/s or 0.2512 m/s
Where,
V = velocity of particle.
A = amplitude = 8cm
ω = Angular velocity
We know that ω = 2π/t [ given t = 2s]
V = A × 2π/t
= 8 × 2π/2
= 8 × 3.14
= 25.12 cm/s or 0.2512 m/s
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