Question

a particle executes a simple harmonic motion of time period t. Find the time taken by the particle to go directly from its mean position to half the amplitude

Answer 1

Answer:

Let equation of shm is

X

x=Asin(wt)

Put x=A/2

1/2=sinwt

wt=pi/6

t=(pi/6)/w

t=(pi/6)/(2pi/T)

t=T/12

Explanation:

T=time period of oscillation.