Question

a particle executes an shm of period 1.2sec and amplitude 8 cm.find the time it takes to travel 3cm from the positive extremity of its oscillation

Answer 1

Hey dear,

● Answer - t = 0.1712 s

● Explanation-
# Given-
T = 1.2 s
A = 8 cm
x = 8-3 = 5 cm

# Solution-
Angular velocity is given by -
ω = 2π/T
ω = 2π/1.2

Position of the particle form extremity is given by-
x = Acos(ωt)
5 = 8 × cos(2πt/1.2)
0.625 = cos(2πt/1.2)

Taking inverse-
0.8957 = 2πt/1.2
t = (0.8957×1.2)/(2×3.14)
t = 0.1712 s

Time taken is 0.1712 s.

Hope that is useful..

Answer 2

Explanation:

why didi you take cos ()....why not sin()