Physics, asked by narendarrana6227, 7 months ago

A particle executes linear simple harmonic motion with an
amplitude of 3 cm. When the particle is at 2 cm from the
mean position, the magnitude of its velocity is equal to that
of its acceleration. Then its time period in seconds is [2017]
(a) √5/2π (b) 4π/√5
(c) 2π/√3 (d) √5/π

Answers

Answered by sanjay207072
0

Answer:

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Explanation:

option b

Answered by gsarthak326
1

Answer:

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