Question

A particle executes s.H.M. Along a straight line so that its period is 12 sec. The time it takes in traversing a distance equal to half its amplitude from its equilibrium is

Answer 1

Hey mate,

◆ Answer-
t = 1 s

◆ Explanation-
# Given-
x = A/2
T = 12 s
t = ?

# Solution-
Let the particle move in SHM with amplitude A and angular velocity ω.

Equation for displacement of SHM starting from mean position is -
x = Asin(ωt)
A/2 = Asin(ωt)
sin(ωt) = 1/2

Taking inverse,
ωt = π/6
2πt/T = π/6
t = T/12
t = 12/12
t = 1 s

Therefore, particle will take 1 s to travel half the amplitude from mean position.

Hope it helps...