Question

A particle executes s.H.M between x = a to x = +a. The time taken for it in going from 0 to a/2 is t1 and from a/2 to a is t2. Then

Answer 1

Plz complete ur question

Answer 2

t1<t2

it can be seen that acceleration is negative in SHM that is while going from the mean position to word the extreme the velocity of the particle decreases .

That is ~-->Y1 covered in that time T1 will be equal to a Y2 covered in time T2 that is the distance is same but the velocity is decreased so the time T2 will be greater than time T1

also as we know that the velocity is maximum at the mean position and going towards the extreme it decreases source from this also can be calculated that time T2 is greater than time T1 for the same distance travel A/2

but still if you wanna solve this just see the attachement

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khushi here