Question

A particle executes S.H.M from extreme position and covers a distance equal to half of its amplitude in 1 sec. Determine the time period of motion.

Answer 1

                 x = A cos(wt)

Here;    

                 x = A/2    &       t = 1

Now;

                A/2 = A cos (w(1))

                   1/2 = cos (w)

                                                    ∵   w = π/3

Time period (T) = 2π/w

                            = 2π/π/3

                            = 6π/π

                            = 6 sec