Question

A particle executes S.H.M. given by the equation y
=
0.45
sin
2
t
where y is in meter and t is in second. What is the speed of the particle when its displacement is 7.5 cm

Answer 1

Step-by-step explanation:

Given  

A particle executes S.H.M. given by the equation y = 0.45 sin 2 t where y is in meter and t is in second  What is the speed of the particle when its displacement is 7.5 cm

Given y = 0.45 sin 2t

     So 7.5 / 100 = 0.45 sin 2t (since displacement is 7.5 cm)

      So 0.075 = 0.45 sin 2t

    So 0.075 / 0,45 = sin 2t

Now sin 2t = 0.166

We know that speed = a ω cos 2t

                                = 0.45 x 2 √1 – sin^2 2t

                               = 0.9 x 0.98

                               = 0.87

                             = 0.15 √3 m/s

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