A particle executes S.H.M. of time period 8 s and amplitude 4 cm. Find the speed of a particle 2 s after it
passes through mean position
Answers
Answered by
6
Its an little logical question. Answer will be zero in this case.
Let us discuss it.
Time Period of this S.H.M. is 8 seconds. This means it starts from mean position and after going to each position , and it returns to its mean position in 8 seconds.
Thus time taken to go from mean position to one extreme is 8/4 = 2 seconds.
This means, it will be at extreme position when t = 2 seconds after it starts from mean position.
Now, A = x
Using the formula,
v² = ω²(A² - x²)
∴ v² = ω²(A² - A²)
∴ v² = 0
Thus, v = 0.
Thus, speed of the Particle will be zero 2 seconds after it motion starts.
Hope it helps.
Similar questions