Physics, asked by anubhaviaankhen2657, 1 month ago

A particle executes S.H.M with amplitude A. If the time taken by the particle to travel from -A to A/2 is 4 seconds, its time period is

Answers

Answered by ProximaNova
6

Answer:

5.33 s

Explanation:

Amplitude is the maximum distance from mean position of an oscillatong particle.

In am complete oscillstion, the object goes 2 times to extreme position and then return to mean position. Thus it travels distance of 4A in one oscillation

Time to cover distance -A to A/2 = 4 sec

Time taken to cover distance 3A/2 = 4 sec

Time period = time to travel 2A distance

Time period = 4 × 2/3 × 2 = 16/3 = 5.33 s

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