A particle executes shm according to equation x=10cos[2t+/2] , where t is in second. The magnitude of the velocity of the particle at t=1/6s will be:
Answers
Answered by
7
Given equation,
x = 10cos(2t + π/2)
Differentiating both sides of the equation with respect to time.
We get,
v = 10 × 2 -Sin(2t + π/2)
∴ v = -20Sin(2t + π/2)
v = -20Sin(2 × 1/6 + π/2)
∴ v = -20Sin( π/2 + 1/3)
v = -20Cos(1/3)
v = -20 × 0.18
∴ v = -3.60 m/s.
Hence, the velocity of the particle at time 1/6 seconds is 3.6 m/s.
Hope it helps .
Answered by
17
Answer:
31.4 cm/s
Explanation:
look at the given attachment below....I hope it helps you...
Attachments:
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