Question

a particle executes SHM in a line 10cm long.when it passes through the mean position its velocity is 15cm/s .whats the period?

Answer 1

V = ω $\sqrt{A^{2}-d^{2}}$   

where signs have their usual meanings 

d = 0 at mean position 

15= ω $\sqrt{100-0}$   

⇒ ω = 1.5 s⁻¹

T = 2π/ω ⇒ T = 4π/3 s ANSWER