Physics, asked by iamshakilaifham, 1 year ago

a particle executes SHM in a line 10cm long.when it passes through the mean position its velocity is 15cm/s .whats the period?

Answers

Answered by Anonymous
0
V = ω  \sqrt{A^{2}-d^{2}}   

where signs have their usual meanings 

d = 0 at mean position 

15= ω  \sqrt{100-0}   

⇒ ω = 1.5 s⁻¹

T = 2
π/ω ⇒ T = 4π/3 s ANSWER
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