a particle executes SHM in a line 10cm long.when it passes through the mean position its velocity is 15cm/s .whats the period?
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V = ω
where signs have their usual meanings
d = 0 at mean position
15= ω
⇒ ω = 1.5 s⁻¹
T = 2π/ω ⇒ T = 4π/3 s ANSWER
where signs have their usual meanings
d = 0 at mean position
15= ω
⇒ ω = 1.5 s⁻¹
T = 2π/ω ⇒ T = 4π/3 s ANSWER
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