Question

A particle executes shm of amplitude a at what point is its speed half the maximum speed

Answer 1

Answer:

A particle executes SHM with amplitude 'A' and angular frequency 'ω'

Vmax = Aω

V = ω√(A^2 - x^2)

Half the maximum speed V = ωA/2

ωA/2 = ω√(A^2 - x^2)

A^2/2 = (A^2 - x^2)

x^2 = A^2 - A^2/2 = A^2/2

x = ±A/√2

At a distance ±A/√2 from the mean position the speed will be half the maximum speed