A particle executes SHM with a period of 0.001 sec and an amplitude of 10 cm.Find it's acceleration when it is at a distance of 3 cm from its mean position
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1183152m/s2
Explanation:
as time period is low,acceleration is fast
as per formula A=W^2X we may not consider amplitude here so that
a=4(pi)^2f^2X
then we got a=1183152m/s^2
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Explanation:
in this way we can solve the problem my friend
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