Question

A particle executes SHM with a time period of 2s and amplitude 5cm find i) displacement after 1/3 sec starting from mean position

Answer 1

Time period t=2s
Amplitude a=5cm
Time after which displacement is to be calculated is t=1/3
At that time a=0
->As we all know w=2¶/t
w=2¶/2=¶
Now:
X=asin(wt+a)
X=5sin(¶×1/3+0)
X=5sin(¶/3)
X=5*sin60
X=5*(3/2)^1/2
X=8.66/2
X=4.33
X=4cm approx hpoe it helps mark as brainliest