Question

A particle executes SHM with an amplitude of 0.2m. Its displacement when its
phase is 90° if particle starts from mean position is
1) 0.1 m
2) 0.2 m
3) 0.4 m
4)
$0.1 \div \sqrt{2}$




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Answer 1

Answer:

Option 2) is correct

Explanation:

For SHM

displacement equation:

y=A sin(ωt+φ)  # equation starting from mean position

where,

    y is displacement

    A is amplitude

    φ is initial phase

    (ωt+φ) is phase

given A=0.2,phase=90°

so

  y=0.2 * sin 90°

    =0.2 * 1

    =0.2 m

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