Physics, asked by Nisarg21, 1 year ago

A particle executes SHM with time period
T and amplitudeA .The maximum possible average velocity in time
T/4 is

Answers

Answered by Anonymous

8

We know that,AVERGAE SPEED=TOTAL DISTANCE(D)/TOTAL TIME TAKE(t)Here,D=4nA(4A distance in one oscillation)t=nTD/t=4A/T

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