Physics, asked by ambarish2208, 11 months ago

A particle executes simple harmonic motion with a frequency v. The frequency with which the kinetic energy oscillates is
(a) v/2
(b) v
(c) 2 v
(d) zero

Answers

Answered by qwcricket
0

The frequency with which the kinetic energy oscillates is 2v (option c is correct)

  1. The distance is given in the simple harmonic motion (SHM) is
  2. x= Asin(wt)
  3. The velocity is given as V=dx/dt
  4. V=Awcos(wt)
  5. The kinetic energy is given as
  6. K.E=\frac{1}{2}MV^{2}
  7. K.E =\frac{1}{2}M A^{2}w^{2}cos^{2} (wt)
  8. K.E =\frac{1}{2}M A^{2}w^{2}\frac{(1+cos(2wt))}{2} =\frac{1}{4}M A^{2}w^{2}(1+cos(2wt))
  9. The frequency of ossification is 2w .
Answered by shilpa85475
0

The oscillation of the kinetic energy with which the frequency is 2v.

Explanation:

  • The value of the kinetic energy changes to maximum from zero, twice. This is because of one complete oscillation.  
  • In physics, a single oscillation is nothing but one complete cycle. So, over the term cycles, the term oscillation is preferred when there is rapid occurrence of cycles.
  • Frequency is defined as the rate in which the cycles occurring via some units of time.
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