Question

A particle executes simple harmonic motion with
amplitude A and time period T. The average speed of
the particle over n complete oscillations is:
(a) 0.
(b) A/nT
(c) 4 A/NT
(d) 4A/T​

Answer 1

Answer:

4A/T

Explanation:

because harmonic is with simple amplitude

Answer 2

Given that,

Amplitude = A

Time period = T

A particle executes simple harmonic motion.

The particle over n complete oscillations it means time period of particle is nT.

We know that,

A particle covered the distance in one oscillation is 4A.

So, The distance covered in n oscillation is

$d=4nA$

We need to calculate the average speed of the particle in n oscillation

Using formula of average speed

$v=\dfrac{D}{T}$

Where, D = total distance

T= total time period

Put the value into the formula

$v=\dfrac{4nA}{nT}$

$v=\dfrac{4A}{T}$

Hence, The average speed of the particle in n oscillation is $\dfrac{4A}{T}$

(d) is correct option

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Topic : average speed

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