A Particle Executes Simple Harmonic Motion With An Amplitude Of 10Cm. If The Angular Frequency Of Oscillation Of Particle Is 20 Rad/S, The Acceleration Of The Particle Of Its Extreme Position Is
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Answer:
Explanation:-
As we know that formula of acceleration at extreme pos. obtained after differentiating velocity formula w.r.t time
=. -wA
Where w is angular frequency and A is amplitude.
ACC.to ques.
Amplitude=10cm/100=0.1 m
w=20rad/s
By putting values in above formula we get:-.
Acc.=-20×0.1=-2m/s^-2
Hope it helps.
Answered by
0
Answer:
As we know that formula of acceleration at extreme pos. obtained after differentiating velocity formula w.r.t time
=. -wA
Where w is angular frequency and A is amplitude.
ACC.to ques.
Amplitude=10cm/100=0.1 m
w=20rad/s
By putting values in above formula we get:-.
Acc.=-20×0.1=-2m/s^-2
Explanation:
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