A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position the velocity of the particle is 10 cm / s. The distance of the particle from the mean position when its speed becomes 5 cm / s.
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From the figure ,
We know simple harmonic motion satisfied condition.
a = -w²x
Where A , w is positive constant
(A) at t = 0.3
X is negative
Slope of graph at t = 0.3 negative so, velocity < 0 .
a will be positive because displacement is negative { a=-w²x}
(B) at t = 1.2
X is positive { shown in figure }
slope of displacement - time graph is positive at t = 1.2 so, velocity will be positive .
acceleration will be negative because displacement is positive .
(C) at t = -1.2
Displacement is negative.
Slope of graph at t= -1.2 is positive so, velocity at t = -1.2 is positive .
Acceleration will be positive because displacement is negative.
Explanation:
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