Question

A particle executes simple harmonic motion with an amplitude of 4 cm. At the mean position the velocity of the particle is 10 cm / s. The distance of the particle from the mean position when its speed becomes 5 cm / s.

Answer 1

Further u can solve by yourself .hope it will help

Answer 2

Answer:

From the figure ,

We know simple harmonic motion satisfied condition.

a = -w²x

Where A , w is positive constant

(A) at t = 0.3

X is negative

Slope of graph at t = 0.3 negative so, velocity < 0 .

a will be positive because displacement is negative { a=-w²x}

(B) at t = 1.2

X is positive { shown in figure }

slope of displacement - time graph is positive at t = 1.2 so, velocity will be positive .

acceleration will be negative because displacement is positive .

(C) at t = -1.2

Displacement is negative.

Slope of graph at t= -1.2 is positive so, velocity at t = -1.2 is positive .

Acceleration will be positive because displacement is negative.

Explanation: