Question

A particle executes simple harmonic motion with time period 2 second and amplitude 5 cm what is the maximum magnitude of its velocity​

Answer 1

Hey there !

We know that

• v = w . A ( where w = omega /angular

velocity and A is amplitude )

• T = 2second and A = 5cm

• w = 2π/ T → w= 2π/2 = π

Now ,

v = w.A

= π . 5

= 5π cm/s