Question

A particle executes the motion described by x(t) = x, [1 - eBP];t20 the initial velocity of particle is??​

Answer 1

Answer:

Explanation:

As x(t) = x0(1-e-yt) (a) For velocity,  v(t) =  d x ( t ) d t = + x 0 γ e − y t dx(t)dt=+x0γe−yt For acceleration, a ( t ) = d v ( t ) d t = − x 0 γ 2 e ⊔ γ t a(t)=dv(t)dt=−x0γ2e⊔γt (b) When t = 0; x(t) = x0(1−e−0) = x0(1−1) = 0 v(t = 0) = x0γe−0 = x0γ(1) = γx0 (c) (i) x(t) is maximum, when- t = ∞, x(t) = x0 x(t) is minimum, when t = 0, x(t) = 0 (ii) v(t) is maximum, when t=0, v(0) = x0γ v(t) is minimum, when t = ∞, v(∞) = 0 (iii) a(t) is maximum, when t = ∞, a(∞) = 0 a(t) is minimum, when t = 0, a(0) = -x0γRead more on Sarthaks.com - https://www.sarthaks.com/1028791/a-particle-executes-the-motion-described-by-x-t-x0-1e-yt-t-0-x0-0