Question

A particle executing circular motion of radius 5m and linear speed of 3m/s which is increasing at the rate of 2m/ s^2 .what is the acceleration of particle?​

Answer 1

Answer:

Equations

Equation Symbol breakdown

v = r ω v = r \omega v=rω v v v is linear speed, r is radius, ω is angular speed.

T = 2 π ω = 1 f T = \dfrac{2\pi}{\omega} = \dfrac{1}{f} T=ω2π=f1 T T T is period, ω is angular speed, and f is frequency