Question

A particle executing S.H.M has acceleration 12 cm/s² at 3 cm from its mean position. Time period of particle is

Answer 1

Answer:

Time period is T= 2π√l/√a

2π√3/√12

2π/2=πsec is the answer.

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Answer 2

Explanation:

a= 12cm/S2

disp (L)=3cm

T=2π√displecement /acceleration

T=2π√3/12

T=2π 1/2

T=π 3.14 answer