A particle executing SHM has a time period of 2 seconds. If it starts from rest at a distance of 25 cm from the mean position, determine the maximum velocity and the
velocity when it has travelled 10 cm.
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Answer:
p(X)=p(-3)
therefore X=-3
x+3=0 ( you told me)
let put the Value of X=-3
X²+kx-2 = -3×-3+k×-3-2
9-3k-2
7-3k
-7=-3k
7=3k
k=7/3
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