A particle executing SHM has amplitude 0.01m and
frequency 60 Hz. The maximum acceleration of particle
IS
(1) 60m/s2
(3) 120m/s2
(2) 80m/s2
(4) 144m/s?
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Answer: HELP U
Explanation:
Maximum acceleration of particle
=aω2=a(2πf)2
=4aπ2f2
=4×0.01×π2×(60)2
=144π2ms−2
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