Question

A particle executing SHM has maximum velocity of 1.00ms and maximum acceleration of 1.57ms calculate time period

Answer 1

Answer:

4.00 sec

Explanation:

V(max) = wA

a(max) = w^2 A

Dividing both eqn

w = a(max)/v(max)

w = 1.57 rad/sec

T = 2π/w

T = (2 x 3.14)/1.57 = 4.00 sec