Question

A particle executing simple harmonic motion is given by y= 6sin 6(pie.t) calculate the value of frequency of the particle.




Please answer correctly I have exam tomorrow.

Answer 1

Explanation:

equation of shm is =Asin(wt)

comparing this we get w=6pie

w=2pie f

f=w/2pie=6pie/2pie =3hz

Answer 2

The frequency of the particle is 3 Hz.

Explanation:

Given that,

A particle executing simple harmonic motion is given by :

$y=6\ \sin(6\pi t)$...........(1)

The general equation of SHM is given by :

$y=A\ \sin(\omega t)$.........(2)

On comparing equation (1) and (2) we get :

$\omega=6\pi$  

Since, $2\pi f = \omega$

So,

$6\pi =2\pi f$

f = 3 Hz

So, the frequency of the particle is 3 Hz.

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