A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
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1
Answer:
here is your answer : )
Explanation:
V
max
=aω⇒f=
2π
ω
=
2πa
V
max
=
2π×5
31.4
=
10π
31.4
=1Hz
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