Question

A particle experiences a constant acceleration for 6 second after starting from rest. If it travels a distance d1
in the first two second, d2 in the next two seconds and a distance d3 in the last 2 second, then
(1) d1:d2:d3=1:1:2
(2) d1: d2: d3= 1:2:3
(3) d1: d2: d3= 1:3:5
(4) d1: d2: d3 = 1:5:9
​

Answer 1

Answer:

ans is 3rd option

Explanation:

i hope u understand

Answer 2

We have,

Constant acceleration = a [Let]

Initially, velocity = 0

Formula,

s = ut + ½at²

But here,

s = ½at²

D1:-

S1 = ½a(2)² = 2a

D2:-

D2 = ½a(4)² - ½a(2)² = ½a(4² - 2²) = ½a(12) = 6a

D3:-

D3 = ½a(6)² - ½a(4)² = ½a(6² - 4²) = ½a(36 - 16)

= ½a(20) = 10 a

Finding ratios:-

D1:D2:D3 = 2a : 6a : 10 a = 1:3:5.

∴ (3) is the correct option.