A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels from a distance s1 in first 10 seconds and distance s2 in the next 10 seconds ,then the relation between s1 and s2 is?
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Given
initial velocity = u = 0
acceleration = a = constant .
S1 = uT1 + aT²2
S1 = 0 + aT²/2
S1 = aT²/2
Final velocity V after 10s is
V = u + aT
V = aT
S2 = uT + aT²/2
S2 = VT + aT²/2
S2 = aT + aT²/2
S2 = 2aT+aT²/2
divide 1 and 2
S1/S2 = aT²/2 × 2/aT(2+aT)
S1/S2 = aT/2+aT
S1/S2 = 10a/2+10a
S1/S2 = 5a/1+5a
S1 ,= S2(5a/1+5a)
where a is acceleration
initial velocity = u = 0
acceleration = a = constant .
S1 = uT1 + aT²2
S1 = 0 + aT²/2
S1 = aT²/2
Final velocity V after 10s is
V = u + aT
V = aT
S2 = uT + aT²/2
S2 = VT + aT²/2
S2 = aT + aT²/2
S2 = 2aT+aT²/2
divide 1 and 2
S1/S2 = aT²/2 × 2/aT(2+aT)
S1/S2 = aT/2+aT
S1/S2 = 10a/2+10a
S1/S2 = 5a/1+5a
S1 ,= S2(5a/1+5a)
where a is acceleration
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