A particle falling under gravity displaces 80 ft in a certain second .How long does it take to displace 112 ft ? [g=32 ft/s^2]
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1
Answer:
1 sec
Explanation:
Let us consider the velocity of particle when it completes 80 ft is V and this velocity will be initial velocity for 112 ft height. Let us consider it takes t time.
g=32ft/s
2
V
2
=u
2
+2gh
V
2
=O
2
+2×32×80
V=
64×80
V=8×4
5
V=71.55 ft/s
now, h=vt+0.5×g×t
2
112=71.55t+0.5×32×t
2
On solving,
t=−h±
h
2
−4ac
/2α
t=1 seconds
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