A particle falls freely from the top of a tower and during last second of its motion it falls (5/9) of the whole height of the tower. Find the height of tower in meters. (Ans t=3sec,h=44.145m)
Answers
Answer aa gaya calculator se check karlo bhai
figure me solution hai explained
Explanation:
Ek follow to banta hai kuch naya sikhna hai to uska topic batao science me me uske bare me bataunga
The height of the tower is 44.1 m/s.
Given,
the fraction of tower it covers in its last-second: 5/9th
time taken = 3 s
To Find,
The height of the tower
Solution,
We have been given a situation of free fall of a particle from the top of a tower.
Therefore, the initial velocity of the particle, u = 0 m/s
Given that the time taken = 3 s
We have to find the height of the tower.
Let the time taken by the tower to fall down be t
Then, s = ut + 1/2 at²
⇒ h = 1/2 at²
Here, a is the acceleration due to gravity, g = 9.8 m/s
⇒ h = 1/2 gt²
⇒ h = 1/2 × 9.8 × ²
⇒ h = 4.9 × 9
⇒ h = 44.1 m/s
#SPJ3