a particle falls the distance of 122.5 m freely under gravity what is other time of Fall and final velocity of the particle
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t = sqrt(2H/g)
= sqrt(2 × 122.5 / 9.8)
= 5 seconds
v = sqrt(2Hg)
= sqrt(2 × 122.5 × 9.8)
= 49 m/s
Time taken to fall: 5 seconds
Final velocity of particle: 49 m/s
= sqrt(2 × 122.5 / 9.8)
= 5 seconds
v = sqrt(2Hg)
= sqrt(2 × 122.5 × 9.8)
= 49 m/s
Time taken to fall: 5 seconds
Final velocity of particle: 49 m/s
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