Question

A particle follows the path ABC where AB=BC=l. Find the distance traveled by particle and its displacement.

Answer 1

Answer:

$l \sqrt{2}$

given :-

AB=BC= l

so,

path length = AB+BC

= l+l

= 2l

So,

a/q

displacement =

$\sqrt{ {ab}^{2} + {bc }^{2} }$

$\sqrt{ {l }^{2} + {l}^{2} }$

$\sqrt{2 {l}^{2} }$

$l \sqrt{2}$