Question

A particle from rest moves with 8 m/s2 acceleration. what is the distance travelled by particle at 5 sec?

Answer 1

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Here is ur answer :-

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Given,

Initial velocity, u = 0

Acceleration, a = 8m/s^2

Time, t = 5sec

So, first we have to find final velocity

v = u + at

=> v = 0 + 8*5

=> v = 40m/s

So, final velocity is 40m/s

Now we find the distance.

2as = v^2 - u^2

2 * 8 * s = (40)^2 - 0^2

16s = 1600

s = 1600/16

s = 100m

So, the distance travelled is 100 m

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Hope it helps!!