Question

A particle goes from A to B with a speed of 40km/h and B to C with a speed of 60km/h. If AB = 6BC,
average speed in km/h between A and C is​

Answer 1

Answer:

42

Explanation:

avg speed equals total distance divided by total time

avg speed= (AB+BC)/(AB/40 + BC/60)

and AB=6BC

Answer 2

The average speed between A and C is 42 km/hr.

Explanation:

• Let t₁ and t₂ are the time taken by particle going from A to B with a speed of 40 km/h and B to C with a speed of 60 km/h respectively.

• Also, AB = 6 BC .....(1)

• Distance moved by particle from A to B is 40 t₁ and the distance moved by particle from B to C is will be 60 t₂.
• Average speed is given by total distance divided by total time taken

So,

$v=\dfrac{40t_1+60t_2}{t_1+t_2}$.........(2)

Equation (10 becomes :

$40t_1=6\times 60t_2\\\\40t_1=360t_2\\\\t_1=9t_2$

So, equation (2) becomes :

$v=\dfrac{40(9t_2)+60t_2}{(9t_2)+t_2}\\\\v=\dfrac{360t_2+60t_2}{9t_2+t_2}\\\\v=\dfrac{360+60}{9+1}\\\\v=42\ km/hr$

So, the average speed between A and C is 42 km/hr.

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