Question

A particle goes uniformly in circular motion with an angular speed π/8 rad/sec.what is its time period?​

Answer 1

HELLO THERE!

The time period and the angular velocity of a body when it is in an uniform circular motion is inter-related as:

$T = \frac{2\pi}{\omega}$

That is, if you know the Time period, you can calculate the angular velocity, and vice versa. Here, we know the angular velocity and hence we are to calculate the time period. Here's your answer:

$T = \frac{2\pi}{\frac{\pi}{8}} \\\\ = 16 sec$

Thanks!

Answer 2

Answer:

Time period= 8sec

Explanation:

Since ω=2π/T

Given,

ω= π/ 8

Therefore

π/ 8=2π/ T

T= 8sec