A Particle has a displacement 12 cm towards east and 9 cm towards north and then 6 cm vertically upward. Find the magnitude of sum of this displacemants.
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we get a right angled triangle with sides 12 cm and 15 cm
=>S=(12²+15²)^1/2
=19.2 cm
=>S=(12²+15²)^1/2
=19.2 cm
pkneulkar:
Wrong it's Answer is 17 But how to solve it I Don't know?
no yar ,its answer is 19.2
i think its the correct answer
even I think so :P
haha :D
Answered by
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A Particle has a displacement 12 cm towards east and 9 cm towards
north and then 6 cm vertically upward. Find the magnitude of sum of this
displacemants.
Solution :
The resultant displacement will be the vector resultant of two vectors whose magnitudes are 12 and and 15 .
hence the resultant dispacement = √ (12)^2 + (15)^2
= √(144 + 225)
= √(369)
= 19.18
Hope this helps you!!
Solution :
The resultant displacement will be the vector resultant of two vectors whose magnitudes are 12 and and 15 .
hence the resultant dispacement = √ (12)^2 + (15)^2
= √(144 + 225)
= √(369)
= 19.18
Hope this helps you!!
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