Physics, asked by vaishnavtanishq36, 1 month ago

a particle has a displacement of 12m towards east 3m towards north and 4m vertically upwards.the resultant magnitude of these displacements is 1.3x10^xcm.the value of x is ?

Answers

Answered by rakshith0806
1

Explanation:

|R|=1.3×10^x

square root (12×12+3×3+4×4)=1.3×10^x

square root (144+9+16)=1.3×10^x

square root (169)=1.3×10^x

13=1.3×10^x

10^x=10

x=1

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