a particle has a velocity u towards east at t=0. it as acceleration is towards west and is constant . let .ca and xb be the magnitude of the displacement in the first 10 seconds and next 10 seconds (a) xa<Xb (b) xa=xb (c) xa>xb (d) the information is insufficient to decide the relation of .ca with xb.
Answers
Answer:
The relation among Xa and Xb is option (c) Xa>Xb
Explanation:
Since the particle has a constant negative acceleration,
its velocity at any time t is given by,
v = u - at
clearly as t increases v decreases
=> velocity will be lower in the 2nd 10 second period
since distance is directly proportional to velocity
=> distance in the 1st 10 second > distance in the 2nd 10 second
=> Xa > Xb
I hope this answer helps you, please feel free to ask any doubt in the comment section.
A particle has a velocity u towards east at t=0. it as acceleration is towards west and is constant . let .ca and xb be the magnitude of the displacement in the first 10 seconds and next 10 seconds (a) xa<Xb (b) xa=xb (c) xa>xb (d) the information is insufficient to decide the relation of .ca with xb.
a particle has a velocity u towards east
Acceleration is toward west
as acceleration is in opposite direction so acceleration is negative
v = u + at where a is -ve
so v will keep decreasing
so velocity will keep reducing
S = ut + (1/2)at²
t = 10 sec in both cased
V at 10 sec < V at 0 sec
So Displacement in 1st 10 sec will be more than next 10 sec
so Xa > Xb
Option C