Physics, asked by MiniDoraemon, 8 months ago

A particle has an initial velocity 3i + 4j and an acceleration of 0.4i + 0.3j . its speed after 10s is ? [AIEEE 2009]

Answers

Answered by TheLifeRacer

3

Explanation:- Given , u = 3i+4j ; a = 0.4i + 0.3j

V = u + at
= 3i + 4j + (0.4i + 0.3j)*10
=3i + 4j +4i +3j
= 7i+7j

So speed is equal to magnitude of velocity

= √7²+7² = 7√2 Answer

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