A particle has an initial velocity of (3ỉ+4) m/s and a constant acceleration of (4ỉ - 3)) m/s². Its speed after
one second will be equal to:
Answers
Answered by
0
Answer:
Initial velocity of particle
u
= 3
i
^
+4
j
^
Acceleration
a
= 4
i
^
−3
j
^
Final velocity after 1 second
v
=
u
+
a
t
where t=1 s
⟹
v
= (3
i
^
+4
j
^
)+ (4
i
^
−3
j
^
)×1= 7
i
^
+
j
^
Speed after 1 second ∣
v
∣=
7
2
+1
=
50
m I hope you this answer help to you and all of you
Answered by
0
Explanation:
using 1st equation of motion .
v=u+at,
placing the values:-
v=(3i+4)+(4i-3)×1
v=3i+4+4i-3
v=7i+1
so the final velocity = 7i+1
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