Question

A particle has an initial velocity of (3i - 3j)and an acceleration of (4i + 2j). What is the speed after 1s?​

Answer 1

Answer:

u=3i-3j , a=4i-2j , t=1sec

a=v-u//t => 4i-2j=v-{3i-3j}/1 => 4i-2j+3i-3j=v => 7i-5j=v

Answer 2

Answer:

since a = v - u/t.

so, a= (4i + 2j)

u=(3i - 3j)

t= 1 sec

so, (4i + 2j)= v - (3i - 3j)/1

so, 4i + 2j = v - 3i + 3 j

Therefore, v = 4i + 3i +2j - 3j

So, v = (7i - j).